5个回答
若n为一维向量则n=0:50 ;
若n为单一元素在调用的时候加个for循环实现，
for n=0:50
代码...
end
若n为单一元素在调用的时候加个for循环实现，
for n=0:50
代码...
end
M-Lint has detected a call to inv in a multiplication operation.
The inverse of a matrix is primarily of theoretical value, and rarely
finds any use in practical computations. Never use the inverse of a
matrix to solve a linear system Ax=b with x=inv(A)*b,
because it is slow and inaccurate.
Suggested Action
Instead of multiplying by the inverse, use matrix right division (/)
or matrix left division (\). That is:
Replace inv(A)*b with A\b
Replace b*inv(A) with b/A
大致意思是，不要用inv求逆（），而是直接用左除\ 或者右除 / 计算Ax=b 中的x
The inverse of a matrix is primarily of theoretical value, and rarely
finds any use in practical computations. Never use the inverse of a
matrix to solve a linear system Ax=b with x=inv(A)*b,
because it is slow and inaccurate.
Suggested Action
Instead of multiplying by the inverse, use matrix right division (/)
or matrix left division (\). That is:
Replace inv(A)*b with A\b
Replace b*inv(A) with b/A
大致意思是，不要用inv求逆（），而是直接用左除\ 或者右除 / 计算Ax=b 中的x
if isempty(A) ~= 1
。。。
。。。
inv或者A^(-1)
我用英文表示这些变量 如参考资料所示 如果公式有上下标就用底杠隔开 如:theta_max