bat如何打印输出时间戳格式为:2012-07-11 19:28:01 最好能一条指令搞定,别脚本 thx~~

echo %DATE:~0,4%-%DATE:~5,2%-%DATE:~8,2% %TIME:~0,2%:%TIME:~3,2%:%TIME:~6,2%

echo %date:~0,-2% %time:~0,-3%

xp能直接输出，win7只能这样 2012/07/27 13:57:35

修改下即可win7用这个 echo %date:/=-%%time:~0,-3%

echo %date:~,10% %time:~,8%